87=3w^2+6

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Solution for 87=3w^2+6 equation:



87=3w^2+6
We move all terms to the left:
87-(3w^2+6)=0
We get rid of parentheses
-3w^2-6+87=0
We add all the numbers together, and all the variables
-3w^2+81=0
a = -3; b = 0; c = +81;
Δ = b2-4ac
Δ = 02-4·(-3)·81
Δ = 972
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{972}=\sqrt{324*3}=\sqrt{324}*\sqrt{3}=18\sqrt{3}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{3}}{2*-3}=\frac{0-18\sqrt{3}}{-6} =-\frac{18\sqrt{3}}{-6} =-\frac{3\sqrt{3}}{-1} $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{3}}{2*-3}=\frac{0+18\sqrt{3}}{-6} =\frac{18\sqrt{3}}{-6} =\frac{3\sqrt{3}}{-1} $

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